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V602. The '<' operator should probably be replaced with '<<'. Consider inspecting this expression.
The analyzer has detected a potential error that may be caused by a misprint. It is highly probable that the '<<' operator must be used instead of '<' in an expression.
Consider the following code sample.
void Foo(unsigned nXNegYNegZNeg, unsigned nXNegYNegZPos,
unsigned nXNegYPosZNeg, unsigned nXNegYPosZPos)
{
unsigned m_nIVSampleDirBitmask =
(1 << nXNegYNegZNeg) | (1 < nXNegYNegZPos) |
(1 << nXNegYPosZNeg) | (1 << nXNegYPosZPos);
...
}The code contains an error, since it is the '<' operator that is written by accident in the expression. This is the correct code:
unsigned m_nIVSampleDirBitmask =
(1 << nXNegYNegZNeg) | (1 << nXNegYNegZPos) |
(1 << nXNegYPosZNeg) | (1 << nXNegYPosZPos);Note.
The analyzer considers comparisons ('<', '>') odd if their result is used in binary operations such as '&', '|' or '^'. The diagnostic is more complex but we hope you understand the point in general. On finding such expressions the analyzer emits the V602 warning.
If the analyzer produces a false positive error, you may suppress it using the "//-V602" comment. But in most cases you'd better rewrite this code. It's not a good practice to handle expressions of the 'bool' type using binary operators: it makes the code unevident and less readable.
This diagnostic is classified as:
You can look at examples of errors detected by the V602 diagnostic. |
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