To get a trial key
fill out the form below
Team license
Enterprise license
** By clicking this button you agree to our Privacy Policy statement

Request our prices
New License
License Renewal
--Select currency--
USD
EUR
RUB
* By clicking this button you agree to our Privacy Policy statement

Free PVS-Studio license for Microsoft MVP specialists
** By clicking this button you agree to our Privacy Policy statement

To get the licence for your open-source project, please fill out this form
** By clicking this button you agree to our Privacy Policy statement

I am interested to try it on the platforms:
** By clicking this button you agree to our Privacy Policy statement

Message submitted.

Your message has been sent. We will email you at


If you haven't received our response, please do the following:
check your Spam/Junk folder and click the "Not Spam" button for our message.
This way, you won't miss messages from our team in the future.

>
>
>
V1091. The pointer is cast to an intege…
Analyzer diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Diagnosis of micro-optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
Customer specific requests (C++)
MISRA errors
AUTOSAR errors
OWASP errors (C#)
Problems related to code analyzer
Additional information
Contents

V1091. The pointer is cast to an integer type of a larger size. Casting pointer to a type of a larger size is an implementation-defined behavior.

Sep 07 2022

The analyzer has detected that a pointer is cast to an integer type of a larger size. The result may differ from a programmer's expectation.

According to C and C++ standards, the result of such an expression is implementation-defined. In most implementations the programmer will get the expected result when a pointer is cast to an integer type of the same size.

Consider the following synthetic example:

void foo()
{
  const void *ptr = reinterpret_cast<const void *>(0x80000000);
  uint64_t ui64 = reinterpret_cast<uint64_t>(ptr); // <=
}

The 'ptr' pointer is converted to the 'uint64_t' type with size of 8 bytes. On 32-bit platforms, the size of pointers is 4 bytes. The result of such casting depends on the implementation of the compiler.

So, if the GCC or MSVC compiler is used, the value 0xffff'ffff'8000'0000 will be written to the 'ui64' variable. Meanwhile, Clang will write the value 0x0000'0000'8000'0000.

To convert a 32-bit pointer to a 64-bit integer and avoid the implementation-defined behavior, do the following:

  • Convert a 32-bit pointer to a 32-bit integer
  • Convert the resulting 32-bit integer to a 64-bit integer

To fix the code above, we first convert the pointer to the 'uintptr_t' type. This is the unsigned integer type whose size is always equal to the pointer size. Then we convert the resulting 32-bit integer to the 64-bit integer. Here's the corrected code:

void foo()
{
  const void *ptr = reinterpret_cast<const void *>(0x80000000);
  uint64_t ui64 = static_cast<uint64_t>(reinterpret_cast<uintptr_t>(ptr));
}

Unicorn with delicious cookie
Our website uses cookies to enhance your browsing experience. Would you like to learn more?
Accept