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V6010. The return value of function 'Fo…
Analyzer diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Diagnosis of micro-optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
MISRA errors
AUTOSAR errors
OWASP errors (C#)
Additional information
Contents

V6010. The return value of function 'Foo' is required to be utilized.

May 11 2018

The analyzer has detected a suspicious call on a method whose return value is not used. Calling certain methods doesn't make sense without using their return values.

Consider the following example:

String prepare(String base, int a, double d)
{
  String str =  base + " /\\ " +
                String.valueOf(a) + " /\\ " +
                String.valueOf(d);
  ...
  str.replace("/", "\\");
  ...
  return str;
}

From the code, it becomes obvious that a string calls the method 'replace' but, in doing so, the result of a call is ignored. As it is known, the method 'replace' returns a new changed string and does not change the content of the string, which called this method. Subsequently, a string with a needed substitution will not be used. That is why, code has to be corrected as follows so that the changes would be taken into account:

String prepare(String base, int a, double d)
{
  String str =  base + " /\\ " +
                String.valueOf(a) + " /\\ " +
                String.valueOf(d);
  ...
  str = str.replace("/", "\\");
  ...
  return str;
}

This diagnostic is classified as:

You can look at examples of errors detected by the V6010 diagnostic.

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