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V3031. An excessive check can be simpli…
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V3031. An excessive check can be simplified. The operator '||' operator is surrounded by opposite expressions 'x' and '!x'.

Dec 14 2015

The analyzer has detected a code fragment that can be simplified. In this code, expressions with opposite meanings are used as operands of the '||' operator. This code is redundant and, therefore, can be simplified by using fewer checks.

Consider this example:

if (str == null || (str != null && str == "Unknown"))

In the "str != null && str == "Unknown"" expression, the condition "str != null" is redundant since an opposite condition, "str == null", is checked before it, while both expressions act as operands of operator '||'. So the superfluous check inside the parentheses can be left out to make the code shorter:

if (str == null || str == "Unknown"))

Redundancy may be a sign of an error – for example use of a wrong variable. If this is the case, the fixed version of the code above should look like this:

if (cond || (str != null && str == "Unknown"))

Sometimes the condition is written in a reversed order and on first glance can not be simplified:

if ((s != null && s == "Unknown") || s == null)

It seems that we can't get rid neither of a (s!=null) nor of a (s==null) check. This is not the case. This expression and the case described above, can be simplified:

if (s == null || s == "Unknown")

You can look at examples of errors detected by the V3031 diagnostic.