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V3132. A terminal null is present insid…
Analyzer Diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Diagnosis of micro-optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
MISRA errors
AUTOSAR errors
Additional information
Contents

V3132. A terminal null is present inside a string. The '\0xNN' characters were encountered. Probably meant: '\xNN'.

Aug. 27, 2012

The analyzer detected a likely error that has to do with the presence of a terminal null inside a string.

This error is typically caused by a typo. For example, the sequence "\0x0A" will be interpreted as the following four-byte sequence: { '\0', 'x', '0', 'A' }.

If you want to specify a character code in hexadecimal format, you need to write the 'x' character immediately after the '\' character. If you write the sequence "\0" instead, the compiler will interpret it as zero (in octal format). See also:

Consider the following example:

String s = "string\0x0D\0x0A";

When trying to print this string, the newline escape characters will not be processed. Printing functions will stop at the null terminator, '\0'. To fix this error, the sequence "\0x0D\0x0A" needs to be replaced with "\x0D\x0A".

Fixed code:

String s = "string\x0D\x0A";

This diagnostic is classified as:

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