V6028. Identical expression to the left and to the right of compound assignment.
The analyzer detected identical subexpressions to the left and to the right of a compound assignment operator. This operation may be incorrect or meaningless, or can be simplified.
Consider the following example:
x += x + 5;
Perhaps the programmer simply wanted to add the value 5 to the 'x' variable. In that case, the fixed code would look like this:
x = x + 5;
Or perhaps they wanted to add the value 5 but wrote an extra 'x' variable by mistake. Then the code should look like this:
x += 5;
However, it is also possible that the code is written correctly, but it looks too complicated and should be simplified:
x = x * 2 + 5;
Now consider the following example:
x += x;
This operation is equivalent to multiplying the value of a variable by two. This is what a clearer version would look like:
x *= 2;
Here is one more expression:
y += top - y;
We are trying to add the difference of the variables 'top' and 'y' to the 'y' variable. Resolving this expression produces the following result:
y = y + top – y;
It can be simplified, as the 'y' variable is subtracted from itself, which does not make sense:
y = top;
You can look at examples of errors detected by the V6028 diagnostic.