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V607. Ownerless expression 'Foo'.
Analyzer Diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Diagnosis of micro-optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
MISRA errors
AUTOSAR errors
Additional information
Contents

V607. Ownerless expression 'Foo'.

Jun 07 2012

The analyzer has detected a potential error: an extra expression in the code. Such "lost" expressions most often occur in the code when the key word return is missing or due to careless code refactoring.

Consider this sample:

void Run(int &a, int b, int c, bool X)
{
  if (X)
    a = b + c;
  else
    b - c; 
}

The program text is incomplete because of the misprint. It compiles well but has no practical sense.

This is the correct code:

void Run(int &a, int b, int c, bool X)
{
  if (X)
    a = b + c;
  else
    a = b - c; 
}

Sometimes "lost" expressions do have practical sense. For example, the analyzer won't generate the warning for the following code:

struct A {};
struct B : public A {};
...
void Foo(B *p)
{
  static_cast<A*>(p);
  ...
}

The "static_cast<A*>(p);" expression here checks that the 'B' class is a inherits of the 'A' class. If it is not so, a compilation error will occur.

As another example, we can cite the following code intended to suppress the compiler-generated warnings about unused variables:

void Foo(int a, int b)
{
  a, b;
}

The analyzer won't generate the V607 warning in this case.

This diagnostic is classified as:

You can look at examples of errors detected by the V607 diagnostic.

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