Our website uses cookies to enhance your browsing experience.
Accept
to the top
close form

Fill out the form in 2 simple steps below:

Your contact information:

Step 1
Congratulations! This is your promo code!

Desired license type:

Step 2
Team license
Enterprise license
** By clicking this button you agree to our Privacy Policy statement
close form
Request our prices
New License
License Renewal
--Select currency--
USD
EUR
* By clicking this button you agree to our Privacy Policy statement

close form
Free PVS‑Studio license for Microsoft MVP specialists
* By clicking this button you agree to our Privacy Policy statement

close form
To get the licence for your open-source project, please fill out this form
* By clicking this button you agree to our Privacy Policy statement

close form
I am interested to try it on the platforms:
* By clicking this button you agree to our Privacy Policy statement

close form
check circle
Message submitted.

Your message has been sent. We will email you at


If you haven't received our response, please do the following:
check your Spam/Junk folder and click the "Not Spam" button for our message.
This way, you won't miss messages from our team in the future.

>
>
>
V3060. A value of variable is not modif…
menu mobile close menu
Analyzer diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Micro-Optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
Customer specific requests (C++)
MISRA errors
AUTOSAR errors
OWASP errors (C#)
Problems related to code analyzer
Additional information
toggle menu Contents

V3060. A value of variable is not modified. Consider inspecting the expression. It is possible that other value should be present instead of '0'.

Feb 04 2016

The analyzer detected a suspicious bitwise expression. This expression was meant to change certain bits in a variable, but the value this variable refers to will actually stay unchanged.

Consider the following example:

A &= ~(0 << Y);
A = A & ~(0 << Y);

The programmer wanted to clear a certain bit in the variable's value but made a mistake and wrote 0 instead of 1.

Both expressions evaluate to the same result, so let's examine the second line as a clearer example. Suppose we have the following values of the variables in bit representation:

A = 0..0101

A = 0..0101 & ~(0..0000 << 0..00001)

Shifting the value 0 by one bit to the left won't change anything; we'll get the following expression:

A = 0..0101 & ~0..0000

Then, the bitwise negation operation will be executed, resulting in the following expression:

A = 0..0101 & 11111111

After executing the bitwise "AND" operation, the original and resulting expressions will turn out to be the same:

A = 0..0101

The fixed version of the code should look like this:

A &= ~(1 << Y);
A = A & ~(1 << Y);

This diagnostic is classified as: