V3060. A value of variable is not modified. Consider inspecting the expression. It is possible that other value should be present instead of '0'.
The analyzer detected a suspicious bitwise expression. This expression was meant to change certain bits in a variable, but the value this variable refers to will actually stay unchanged.
Consider the following example:
A &= ~(0 << Y); A = A & ~(0 << Y);
The programmer wanted to clear a certain bit in the variable's value but made a mistake and wrote 0 instead of 1.
Both expressions evaluate to the same result, so let's examine the second line as a clearer example. Suppose we have the following values of the variables in bit representation:
A = 0..0101
A = 0..0101 & ~(0..0000 << 0..00001)
Shifting the value 0 by one bit to the left won't change anything; we'll get the following expression:
A = 0..0101 & ~0..0000
Then, the bitwise negation operation will be executed, resulting in the following expression:
A = 0..0101 & 11111111
After executing the bitwise "AND" operation, the original and resulting expressions will turn out to be the same:
A = 0..0101
The fixed version of the code should look like this:
A &= ~(1 << Y); A = A & ~(1 << Y);
This diagnostic is classified as: