The analyzer has detected a potential error: the first operator in the 'switch' operator's block is not the 'case' operator. It causes the code fragment never to get control.
Consider this example:
char B = '0';
int I;
...
switch(I)
{
B = '1';
break;
case 2:
B = '2';
break;
default:
B = '3';
break;
}
Assignment "B = '1';" will never be performed. This is the correct code:
switch(I)
{
case 1:
B = '1';
break;
case 2:
B = '2';
break;
default:
B = '3';
break;
}
This diagnostic is classified as:
|
You can look at examples of errors detected by the V622 diagnostic. |
Was this page helpful?
Your message has been sent. We will email you at
If you do not see the email in your inbox, please check if it is filtered to one of the following folders:
Take
a chance!