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V3117. Constructor parameter is not use…
Analyzer diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Diagnosis of micro-optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
MISRA errors
AUTOSAR errors
OWASP errors (C#)
Additional information
Contents

V3117. Constructor parameter is not used.

Sep 12 2016

The analyzer detected a constructor with an unused parameter.

For example:

public class MyClass
{
  protected string _logPath;
  public String LogPath { get { return _logPath; } }
  
  public MyClass(String logPath) // <=
  {
    _logPath = LogPath;
  }
}

It seems that the programmer made a typo and wrote 'LogPath' instead of 'logPath', which resulted in not using the constructor's parameter anywhere in the code. The fixed version:

public class MyClass
{
  protected string _logPath;
  public String LogPath { get { return _logPath; } }
  
  public MyClass(String logPath) // <=
  {
    _logPath = logPath;
  }
}

Consider one more example.

public class MyClass
{
  public MyClass(String logPath) // <=
  {
    //_logPath = logPath;
  }
}

If you deliberately avoid using a constructor's parameter, we recommend that you mark the constructor with the 'Obsolete' attribute.

public class MyClass
{
  [Obsolete]
  public MyClass(String logPath) // <=
  {
    //_logPath = logPath;
  }
}

You can look at examples of errors detected by the V3117 diagnostic.

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