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V577. Label is present inside switch().…
Analyzer diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Diagnosis of micro-optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
MISRA errors
AUTOSAR errors
OWASP errors (C#)
Additional information
Contents

V577. Label is present inside switch(). Check for typos and consider using the 'default:' operator instead.

Jul 05 2011

The analyzer detected a potential error inside the switch operator. A label is used whose name is similar to 'default'. A misprint is probable.

Consider this sample:

int c = 10;
int r = 0;
switch(c){
case 1:
  r = 3; break;
case 2:
  r = 7; break;
defalt:
  r = 8; break;
}

It seems that after the code's work is done, the value of the 'r' variable will be 8. Actually the 'r' variable will still equal zero. The point is that "defalt" is a label, not the "default" operator. This is the correct code:

int c = 10;
int r = 0;
switch(c){
case 1:
  r = 3; break;
case 2:
  r = 7; break;
default:
  r = 8; break;
}

This diagnostic is classified as:

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