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V627. Argument of sizeof() is a macro, …
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V627. Argument of sizeof() is a macro, which expands to a number. Consider inspecting the expression.

Jul 03 2012

The analyzer has detected a potential error: a macro expanding into a number serves as an argument for the 'sizeof' operator. Using the operator in such a way can cause allocation of memory amount of incorrect size or other defects.

Consider an example:

#define NPOINT 100
...
char *point = (char *)malloc(sizeof(NPOINT));

Executing this code will result in allocation of insufficient memory amount. This is the correct code:

#define NPOINT 100
...
char *point = (char *)malloc(NPOINT);

This diagnostic is classified as:

You can look at examples of errors detected by the V627 diagnostic.

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