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V1008. No more than one iteration of the loop will be performed. Consider inspecting the 'for' operator.
The analyzer has detected a possible error that has to do with using suspicious initial and final values of the counter variable in a 'for' statement. This may break the logic of execution.
Consider the following example of suspicious code:
int c = 0;
if (some_condition)
{
....
c = 1;
}
for (int i = 0; i < c; ++i) {
....
}The loop will iterate either 0 or 1 time; therefore, it can be replaced with an 'if' statement.
int c = 0;
if (some_condition)
{
....
c = 1;
}
if (c != 0)
{
....
}There could also be a mistake in the expression evaluating the value of the variable that the loop counter is compared with. For example, the programmer could have actually meant the following:
int c = 0;
if (some_condition)
{
....
c = 1 + n;
}
for (int i = 0; i < c; ++i)
{
....
}This diagnostic is classified as:
You can look at examples of errors detected by the V1008 diagnostic. |
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