Our website uses cookies to enhance your browsing experience.
Accept
to the top
>
>
>
V6087. InvalidClassException may occur …
menu mobile close menu
Analyzer diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Micro-Optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
Customer specific requests (C++)
MISRA errors
AUTOSAR errors
OWASP errors (C++)
OWASP errors (C#)
Problems related to code analyzer
Additional information
toggle menu Contents

V6087. InvalidClassException may occur during deserialization.

Jul 20 2020

The analyzer has detected a situation where the absence of an available default constructor during deserialization may lead to a 'java.io.InvalidClassException'.

When using the 'java.io.Serializable' interface, the JVM is in total control over serialization. When an object is getting deserialized, memory is allocated for it, and the object's fields are filled with the values from the byte stream without calling the constructor. It is important to remember that if a serializable class has a non-serializable parent, the deserialization mechanism will call the latter's default constructor. If there is no such constructor, a 'java.io.InvalidClassException' is thrown.

Consider the following contrived example:

class Parent {
    private String parentField;

    public Parent(String field) {
        this.parentField = field;
    }

    // ....
}

class Child extends Parent implements Serializable {
    public String childField;

    public Child() {
        super("");
    }

    public Child(String field1, String field2) {
        super(field1);
        this.childField = field2;
    }

    // ....
}

Since the parent class is not serializable, when deserializing the object of class 'Child', the built-in deserialization mechanism will attempt to call the default constructor and throw an exception if no such constructor is found.

For correct serialization, we only need to define an available default constructor in the parent class:

class Parent {
    private String parentField;

    public Parent() {
        this.parentField = "";
    }

    public Parent(String field) {
        this.parentField = field;
    }

    // ....
}

When implementing the 'java.io.Externalizable' interface, user-implemented logic is called: serialization and deserialization are implemented by overriding the methods 'writeExternal' and 'readExternal'. During deserialization, the default public constructor is always called first and only then is the 'readExternal' method called on the resulting object. If no such constructor exists, a 'java.io.InvalidClassException' will be thrown.

class Parent implements Externalizable
{
    private String field;

    public Parent(String field) {
        this.field = field;
    }

    public void writeExternal(ObjectOutput arg0) throws .... {
      // serializable logic
    }

    public void readExternal(ObjectInput in) throws .... {
      // deserializable logic
    }

    // ....
}

This class has no appropriate constructor. An object of this class can be successfully serialized, but an attempt to restore a previously serialized object will result in throwing an exception.

To fix this, we only need to define an available constructor without parameters:

class Parent implements Externalizable
{
    private String field;

    public Parent() {
        this.field = "";
    }


    public Parent(String field) {
        this.field = field;
    }

    // ....
}
close form

Fill out the form in 2 simple steps below:

Your contact information:

Step 1
Congratulations! This is your promo code!

Desired license type:

Step 2
Team license
Enterprise license
** By clicking this button you agree to our Privacy Policy statement
close form
Request our prices
New License
License Renewal
--Select currency--
USD
EUR
* By clicking this button you agree to our Privacy Policy statement

close form
Free PVS‑Studio license for Microsoft MVP specialists
* By clicking this button you agree to our Privacy Policy statement

close form
To get the licence for your open-source project, please fill out this form
* By clicking this button you agree to our Privacy Policy statement

close form
I am interested to try it on the platforms:
* By clicking this button you agree to our Privacy Policy statement

close form
check circle
Message submitted.

Your message has been sent. We will email you at


If you do not see the email in your inbox, please check if it is filtered to one of the following folders:

  • Promotion
  • Updates
  • Spam