Our website uses cookies to enhance your browsing experience.
Accept
to the top
close form

Fill out the form in 2 simple steps below:

Your contact information:

Step 1
Congratulations! This is your promo code!

Desired license type:

Step 2
Team license
Enterprise license
** By clicking this button you agree to our Privacy Policy statement
close form
Request our prices
New License
License Renewal
--Select currency--
USD
EUR
* By clicking this button you agree to our Privacy Policy statement

close form
Free PVS‑Studio license for Microsoft MVP specialists
* By clicking this button you agree to our Privacy Policy statement

close form
To get the licence for your open-source project, please fill out this form
* By clicking this button you agree to our Privacy Policy statement

close form
I am interested to try it on the platforms:
* By clicking this button you agree to our Privacy Policy statement

close form
check circle
Message submitted.

Your message has been sent. We will email you at


If you do not see the email in your inbox, please check if it is filtered to one of the following folders:

  • Promotion
  • Updates
  • Spam

Webinar: Parsing C++ - 10.10

>
>
>
V3174. Suspicious subexpression in a se…
menu mobile close menu
Analyzer diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Micro-Optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
Customer specific requests (C++)
MISRA errors
AUTOSAR errors
OWASP errors (C#)
Problems related to code analyzer
Additional information
toggle menu Contents

V3174. Suspicious subexpression in a sequence of similar comparisons.

Jan 24 2022

The analyzer has detected a code fragment that most likely contains a typo. The chain of same-type comparisons of class members has an expression different from others. This expression compares members with different names, while the rest of the expressions compare members with the same names.

Look at the example:

public void Foo(TestClass a, TestClass b)
{
  if (a.x == b.x && a.y == b.y && a.z == b.y)
  {
    ....
  }
}

In this fragment, expression 'a.z == b.y' is different from the rest expressions in the chain. Most likely, it's a typo that appeared when the developer edited a copied text. The correct code which won't look suspicious for the analyzer:

public void Foo(TestClass a, TestClass b)
{
  if (a.x == b.x && a.y == b.y && a.z == b.z)
  {
    ....
  }
}

The analyzer issues a warning when the length of the comparison chain is more than two expressions.

This diagnostic is classified as: