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V771. The '?:' operator uses constants …
Analyzer diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Diagnosis of micro-optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
MISRA errors
AUTOSAR errors
OWASP errors (C#)
Additional information
Contents

V771. The '?:' operator uses constants from different enums.

Nov 15 2016

The analyzer detected a possible error that has to do with the ternary operator '?:' using constants from different enumerations as its second and third operands.

Consider the following example:

enum OnlyOdd { Not_Odd, Odd };
enum OnlyEven { Not_Even, Even };

int isEven(int a)
{
  return (a % 2) == 0 ? Even : Odd;
}

This function checks if the number passed as an argument is even, but its return value is evaluated using constants from two different enums (OnlyEven::Even and OnlyOdd::Odd) cast to 'int'. This mistake will cause the function to return 1 (true) all the time regardless of the 'a' argument's actual value. This is what the fixed code should look like:

enum OnlyOdd { Not_Odd, Odd };
enum OnlyEven { Not_Even, Even };

int isEven(int a)
{
  return (a % 2) == 0 ? Even : Not_Even;
}

Note. Using two different unnamed enumerations is considered a normal practice, for example:

enum 
{
  FLAG_FIRST = 0x01 << 0,
  FLAG_SECOND = 0x01 << 1,
  ....
};

enum 
{
  FLAG_RW = FLAG_FIRST | FLAG_SECOND,
  ....
};

....
bool condition = ...;
int foo = condition ? FLAG_SECOND : FLAG_RW; // no V771
....
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