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V6012. The '?:' operator, regardless of…
Analyzer Diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Diagnosis of micro-optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
MISRA errors
AUTOSAR errors
Additional information
Contents

V6012. The '?:' operator, regardless of its conditional expression, always returns one and the same value.

May 04 2018

The analyzer has detected a potential error when using the ternary operator "?:". Regardless of the condition's result, one and the same statement will be executed. There is very likely a typo somewhere in the code.

Consider the following, simplest, example:

int A = B ? C : C;

In either case, the A variable will be assigned the value of the C variable.

Let's consider the example, where it is not that easy to notice such an error:

double calc(Box bx, int angle, double scale )
{
  return Math.tan((angle % 2 == 0 ?
         bx.side_x : bx.side_x) * 0.42) * scale;
};

This code has been formatted. In reality, though, it may be written in one line, so it's no wonder that a typo may stay unnoticed. The error here has to do with the member of the "side_x" class being used both times. The correct version of this code should look as follows:

double calc(Box bx, int angle, double scale )
{
  return Math.tan((angle % 2 == 0 ?
         bx.side_x : bx.side_y) * 0.42) * scale;
};

This diagnostic is classified as:

You can look at examples of errors detected by the V6012 diagnostic.

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