Our website uses cookies to enhance your browsing experience.
Accept
to the top
close form

Fill out the form in 2 simple steps below:

Your contact information:

Step 1
Congratulations! This is your promo code!

Desired license type:

Step 2
Team license
Enterprise license
** By clicking this button you agree to our Privacy Policy statement
close form
Request our prices
New License
License Renewal
--Select currency--
USD
EUR
* By clicking this button you agree to our Privacy Policy statement

close form
Free PVS‑Studio license for Microsoft MVP specialists
* By clicking this button you agree to our Privacy Policy statement

close form
To get the licence for your open-source project, please fill out this form
* By clicking this button you agree to our Privacy Policy statement

close form
I am interested to try it on the platforms:
* By clicking this button you agree to our Privacy Policy statement

close form
check circle
Message submitted.

Your message has been sent. We will email you at


If you do not see the email in your inbox, please check if it is filtered to one of the following folders:

  • Promotion
  • Updates
  • Spam

Webinar: Evaluation - 05.12

>
>
>
V3109. The same sub-expression is prese…
menu mobile close menu
Analyzer diagnostics
General Analysis (C++)
General Analysis (C#)
General Analysis (Java)
Micro-Optimizations (C++)
Diagnosis of 64-bit errors (Viva64, C++)
Customer specific requests (C++)
MISRA errors
AUTOSAR errors
OWASP errors (C++)
OWASP errors (C#)
Problems related to code analyzer
Additional information
toggle menu Contents

V3109. The same sub-expression is present on both sides of the operator. The expression is incorrect or it can be simplified.

Aug 09 2016

The analyzer detected identical subexpressions in the left and the right part of an expression with a comparison operator. This operation is incorrect or meaningless, or can be simplified.

Consider the following example:

if ((x – y) >= (x - z)) {};

The 'x' variable in this fragment is obviously not necessary and can be removed from both parts of the expression. This is what the simplified version of the code would look like:

if (y <= z) {};

The next example:

if (x1 == x1 + 1) {};

This code contains a true error, as the expression will be false at any value of the 'x1' variable. Perhaps the programmer made a typo, and the code was actually meant to look like this:

if (x2 == x1 + 1) {};

One more example:

if (x < x * y) {};

This expression can also be simplified by removing the 'x' variable:

if (y > 1) {};