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Webinar: C++ semantics - 06.11

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V3001. There are identical sub-expressi…
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V3001. There are identical sub-expressions to the left and to the right of the 'foo' operator.

Oct 08 2015

The analyzer has detected a code fragment that is very likely to have a logical error in it. The program text contains an operator (<, >, <=, >=, ==, !=, &&, ||, -, /, &, |, ^) whose both operands are identical subexpressions.

Consider this example:

if (a.x != 0 && a.x != 0)

In this case, the '&&' operator is surrounded by identical subexpressions "a.x != 0", which enables the analyzer to detect a mistake made through carelessness. A correct version of this code, which won't trigger the diagnostic, should look as follows:

if (a.x != 0 && a.y != 0)

Here's another example of a mistake detected by the analyzer in an application's code:

class Foo {
  List<int> Childs { get; set; }
  ...
  public bool hasChilds() { return(Childs[0] > 0 || Childs[0] > 0); }
  ...
}

In this case, although the code compiles well and without any warnings, it just doesn't make sense. Its correct version should look like this:

public bool hasChilds(){ return(Childs[0] > 0 || Childs[1] > 0);}

The analyzer compares the code blocks, taking into account inversion of the expression's parts in relation to the operator. For example, it will detect the error in the following code:

if (Name.Length > maxLength && maxLength < Name.Length)

This diagnostic is classified as:

You can look at examples of errors detected by the V3001 diagnostic.