Our website uses cookies to enhance your browsing experience.
Contents
The analyzer detected a potential error: there is an excessive comparison in code.
Let me explain this by a simple example:
if (Aa[42] == 10 && Aa[42] != 3)The condition will hold if 'Aa == 10'. The second part of the expression is meaningless. On studying the code, you may come to one of the two conclusions:
1) The expression can be simplified. This is the fixed code:
if (Aa[42] == 10)2) The expression has an error. This is the fixed code:
if (Aa[42] == 10 && Aa[43] != 3)Let's study the example from practice. We have no error here, but the expression is excessive, which might make the code less readable:
while (*pBuff == ' ' && *pBuff != '\0')
pBuff++;The " *pBuff != '\0' " check is meaningless. This is the shortened code:
while (*pBuff == ' ')
pBuff++;This diagnostic rule is classified as:
|
You can look at examples of errors detected by the V590 diagnostic. |
Was this page helpful?
Your message has been sent. We will email you at
If you do not see the email in your inbox, please check if it is filtered to one of the following folders: