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The analyzer has detected duplicate conditions in an if and else if statements' chain. The code in the repeated condition will never execute, which indicates an error.
The example:
if (a == 1) {
foo();
} else if (a == 2) {
bar();
} else if (a == 1) {
baz();
}In this example, the call to baz() is unreachable, since control flow never reaches it. This is probably a logic error, and the fixed code should look like this:
if (a == 1) {
foo();
} else if (a == 2) {
bar();
} else if (a == 3) {
baz();
}Non-identical but equivalent expressions are also taken into account. The example:
if (a & b) {
foo();
} else if (b & a) {
bar();
}This code triggers a warning because a bitwise AND is commutative, so the result will be the same.
This diagnostic rule is classified as:
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