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V6131. Casting to a type with a smaller range will result in an overflow.
The analyzer has detected that an integer value is cast to a data type with a smaller size, which leads to an overflow. This happens because a source value is outside the valid range of the target type.
The example of such an overflow:
static final long MAX_CHUNK_SIZE = 4L * 1024 * 1024 * 1024;
void makeChunks(int fileSize) {
int chunkSize = Math.min(fileSize, (int) MAX_CHUNK_SIZE);
....
}The 4L * 1024 * 1024 * 1024 expression equals 4,294,967,296 (2^32), which is then cast to int. This value exceeds the valid int range ([-2^31..2^31-1]). As a result, the value becomes 0 instead of the expected maximum.
To avoid the overflow, use the long type for all variables and parameters involved in the calculations:
static final long MAX_CHUNK_SIZE = 4L * 1024 * 1024 * 1024;
void makeChunks(long fileSize) {
long chunkSize = Math.min(fileSize, MAX_CHUNK_SIZE);
....
}This diagnostic is classified as:
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