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V6080. Consider checking for misprints. It's possible that an assigned variable should be checked in the next condition.
The analyzer has detected a situation when a variable is initialized or assigned a new value which is expected to be checked in the condition of a subsequent 'if' statement but another variable is checked instead.
This error is demonstrated by the following example:
int ret = foo(....);
if (ret != -1) { .... }
....
int ret2 = bar(....);
if (ret != -1) { .... } // <=Programmers often need to check the value returned by a function but use a wrong variable name in the condition of the 'if' statement. This mistake is typically made when you clone a code fragment but forget to modify the name of the variable in the condition. In the example above, the programmer forgot to change the name 'ret' to 'ret2'.
Fixed version:
int ret2 = bar(....);
if (ret2 != -1) { .... }The following example also demonstrates this mistake:
this.data = calculate(data, ....);
if (data != -1) ....;Both the variable and the field share the same name, which makes it easy to confuse one with the other.
This diagnostic is heuristic; it compares the names of the variables to conclude if there is a typo. It also performs a basic type check to reduce the number of false positives.
This diagnostic is classified as:
You can look at examples of errors detected by the V6080 diagnostic. |
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