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V6041. Suspicious assignment inside the conditional expression of 'if/while/do...while' statement.
The analyzer has detected an 'if'/ 'while'/'do...while' statement whose conditional expression contains the assignment operator '='. Such constructs often signal the presence of errors. The programmer probably intended to use the '==' operator rather than '='.
Consider the following example:
void func(int x, boolean skip, ...)
{
if (skip = true) {
return;
}
...
if ((x > 50) && (x < 150)) {
...
}
...
}This code has a typo in it: rather than checking the 'skip' variable, the programmer is changing its value. As a result, the condition will always be true and the 'return' statement will be executed all the time. Fixed code:
if (skip == true){
return;
}or:
if (skip){
return;
}This diagnostic is classified as:
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