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V3230. Comparison with...
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V3230. Comparison with 'typeof(Nullable<T>)' is meaningless. Calling 'GetType()' on a nullable variable never returns 'Nullable<T>'.

Feb 06 2026

The analyzer has detected a meaningless comparison between the result of calling the GetType method on a Nullable<T> object and typeof(Nullable<T>). The GetType method always returns the underlying type for values of the Nullable<T> type.

The example:

public void Foo<T>(Nullable<T> value) where T : struct
{
  if (value.GetType() == typeof(Nullable<int>))
  {
    ....
  }
  ....
}

In this case, the comparison result is always false, because calling value.GetType() returns the T type.

The fixed code:

public void Foo<T>(Nullable<T> value) where T : struct
{
  if (value.GetType() == typeof(int))
  {
    ....
  }
  ....
}