The analyzer has detected a potential error. The '!=' or '==!' operator should be probably used instead of the '=!' operator. Such errors most often occur through misprints.
Consider an example of incorrect code:
int A, B;
...
if (A =! B)
{
...
}It's most probably that this code should check that the 'A' variable is not equal to 'B'. If so, the correct code should look like follows:
if (A != B)
{
...
}The analyzer accounts for formatting in the expression. That's why if it is exactly assignment you need to perform - not comparison - you should specify it through parentheses or blanks. The following code samples are considered correct:
if (A = !B)
...
if (A=(!B))
...This diagnostic is classified as:
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