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V6003. The use of 'if (A) {...} else if…


V6003. The use of 'if (A) {...} else if (A) {...}' pattern was detected. There is a probability of logical error presence.

The analyzer has detected a potential error in a construct consisting of conditional statements.

Consider the following example:

if (a == 1)
  Foo1();
else if (a == 2)
  Foo2();
else if (a == 1)
  Foo3();

In this code, the 'Foo3()' method will never get control. We are most likely dealing with a logical error here and the correct version of this code should look as follows:

if (a == 1)
  Foo1();
else if (a == 2)
  Foo2();
else if (a == 3)
  Foo3();

This diagnostic is classified as:

You can look at examples of errors detected by the V6003 diagnostic.