# V627\. Argument of sizeof\(\) is a macro, which expands to a number\. Consider inspecting the expression\.

The analyzer has detected a potential error: a macro expanding into a number serves as an argument for the 'sizeof' operator\. Using the operator in such a way can cause allocation of memory amount of incorrect size or other defects\.

Consider an example:

```cpp
#define NPOINT 100
...
char *point = (char *)malloc(sizeof(NPOINT));
```

Executing this code will result in allocation of insufficient memory amount\. This is the correct code:

```cpp
#define NPOINT 100
...
char *point = (char *)malloc(NPOINT);
```