# V6015\. Consider inspecting the expression\. Probably the '\!\='/'\-\='/'\+\=' should be used here\.

The analyzer has detected a potential error, related to a strange usage of operators \('\=\!', '\=\-', '\=\+'\)\. Most likely, their usage is incorrect and one of the following operators should be used here: '\!\=', '\-\=', '\+\='\. 

**Operator '\=\!'**

Example of suspicious code:

```cpp
boolean a = ... ;
boolean b = ... ;
...
if (a =! b)
{
  ...
}
```

It's most probably that this code should check that the 'a' variable is not equal to 'b'\. If so, the correct code should look like follows:

```cpp
if (a != b)
{
  ...
}
```

The analyzer accounts for formatting in the expression\. That's why if it is exactly assignment you need to perform \- not comparison \- you should specify it through parentheses or blanks\. The following code samples are considered correct:

```cpp
if (a = !b)
  ...
if (a=(!b))
  ...
```

**Operator '\=\-'**

Example of suspicious code:

```cpp
int size = ... ;
int delta ... ;
...
size =- delta;
```

This code may be correct, but it is highly probable that there is a misprint and the programmer actually intended to use the '\-\=' operator\. This is the fixed code:

```cpp
size -= delta;
```

If the code is correct, you may type in an additional space between the characters '\=' and '\-' to remove the V6015 warning\. This is an example of correct code where the warning is not generated:

```cpp
size = -delta;
```

**Operator '\=\+'**

Example of suspicious code:

```cpp
int size = ... ;
int delta ... ;
...
size =+ delta;
```

This is the fixed code:

```cpp
size+=delta;
```

If this code is correct, you may remove '\+' or type in an additional space to prevent showing the V6015 warning\. The following is an example of correct code where the warning is not generated:

```cpp
size = delta;
size = +delta;
```