# V590\. Possible excessive expression or typo\. Consider inspecting the expression\.

The analyzer detected a potential error: there is an excessive comparison in code\.

Let me explain this by a simple example:

```cpp
if (Aa[42] == 10 && Aa[42] != 3)
```

The condition will hold if 'Aa \=\= 10'\. The second part of the expression is meaningless\. On studying the code, you may come to one of the two conclusions:

1\) The expression can be simplified\. This is the fixed code:

```cpp
if (Aa[42] == 10)
```

2\) The expression has an error\. This is the fixed code:

```cpp
if (Aa[42] == 10 && Aa[43] != 3)
```

Let's study the example from practice\. We have no error here, but the expression is excessive, which might make the code less readable:

```cpp
while (*pBuff == ' ' && *pBuff != '\0')
  pBuff++;
```

The " \*pBuff \!\= '\\0' " check is meaningless\. This is the shortened code:

```cpp
while (*pBuff == ' ')
  pBuff++;
```