# V583\. The '?:' operator, regardless of its conditional expression, always returns the same value\.

Analyzer found a potential error with utilization of "?:" ternary operator\. Regardless of its conditional expression, the same operation will be performed\. It is quite possible that a misprint is present in the source code\.

Let's review the most basic example:

```cpp
int A = B ? C : C;
```

In all cases the value of C variable will be assigned to the A variable\.

Let's review how such a mistake could appear in the source code of real\-life application:

```cpp
fovRadius[0] =
  tan(DEG2RAD((rollAngleClamped % 2 == 0 ?
  cg.refdef.fov_x : cg.refdef.fov_x) * 0.52)) * sdist;
```

The code here is formatted\. In the program's sources this is a single line of code and it is not surprising that the misprint could be overlooked quite easily\. The essence of an error is that the member of the "fov\_x" structure is used twice\.

The correct code:

```cpp
fovRadius[0] =
  tan(DEG2RAD((rollAngleClamped % 2 == 0 ?
  cg.refdef.fov_x : cg.refdef.fov_y) * 0.52)) * sdist;
```