# V3230\. Comparison with 'typeof\(Nullable<T\>\)' is meaningless\. Calling 'GetType\(\)' on a nullable variable never returns 'Nullable<T\>'\.

The analyzer has detected a meaningless comparison between the result of calling the GetType method on a Nullable<T\> object and typeof\(Nullable<T\>\)\. The GetType method always returns the underlying type for values of the Nullable<T\> type\.

The example:

```cpp
public void Foo<T>(Nullable<T> value) where T : struct
{
  if (value.GetType() == typeof(Nullable<int>))
  {
    ....
  }
  ....
}
```

In this case, the comparison result is always `false`, because calling `value.GetType()` returns the `T` type\.

The fixed code:

```cpp
public void Foo<T>(Nullable<T> value) where T : struct
{
  if (value.GetType() == typeof(int))
  {
    ....
  }
  ....
}
```